Implicit and Explicit Type Conversion by Dividing Two Integers in C

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This program demonstrates implicit and explicit type conversion by dividing two integers to obtain a floating-point result.

C Program

#include <stdio.h>

int main() {
    int a, b;

    printf("Enter two integers: ");
    scanf("%d %d", &a, &b);

    int implicit_result = a / b;
    float explicit_result = (float) a / (float) b;

    printf("Integer division (implicit truncation): %d\n", implicit_result);
    printf("Floating-point division (explicit conversion): %.2f\n", explicit_result);

    return 0;
}

Explanation

  • When both operands of / are int, C performs integer division and silently truncates any decimal part — this is the “implicit” behavior since no conversion is requested but the result type still loses precision.
  • Casting either operand to float using (float) a forces explicit type conversion: C then promotes the whole expression to floating-point arithmetic before dividing, preserving the fractional part.
  • Only one operand needs to be cast for the whole expression to become floating-point, but casting both makes the intent clearer.

Sample Output

Enter two integers: 7 2
Integer division (implicit truncation): 3
Floating-point division (explicit conversion): 3.50

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